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24+4x=4x^2
We move all terms to the left:
24+4x-(4x^2)=0
determiningTheFunctionDomain -4x^2+4x+24=0
a = -4; b = 4; c = +24;
Δ = b2-4ac
Δ = 42-4·(-4)·24
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20}{2*-4}=\frac{-24}{-8} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20}{2*-4}=\frac{16}{-8} =-2 $
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